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BASIC SCRIPT: couting worlds and lines for each file

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Alcorel
 PostPosted: Mon Nov 07, 2011 3:27 pm   

Joined: Mon Nov 07, 2011 3:17 pm
Posts: 1
Hello there,

I'm a begginner in programming BASH scripts and as I'm having a test in two days I have some doubts in some very basic exercices.

One of them asks me to write a script that, for the current directory, counts the number of files present there. This was the easy part:

file=$(ls -l | grep '^-' | wc -l)
echo "The current directory has $file files."

Now the tricky part (at least for me) is that the same exercice asks me to count the words and lines for EACH file present in the current directory. I think I might have to use a FOR cycle to go through each file and apply a simple "wc -lm" but my problem is how do I do it.

Thanks in advance for any help you might give me...
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Patsie
 PostPosted: Tue Nov 08, 2011 12:06 am   
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Joined: Sun Jun 27, 2010 12:57 am
Posts: 192
Code:
nrFiles=0
for file in *; do
  if [ -f "$file" ]; then
    ((nrFiles+=1))
    data=( $(wc -lw "$file") )
    echo "$file: words: ${data[1]} lines: ${data[0]}"
  fi
done
echo "files: $nrFiles"
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choroba
 PostPosted: Tue Nov 08, 2011 4:36 am   
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Joined: Tue Apr 27, 2010 2:28 pm
Posts: 172
Location: Czech Republic
Code:
wc -lw $('ls' -F | grep -v /$ )
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jsz
 PostPosted: Thu Nov 10, 2011 7:59 pm   
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Joined: Wed Jun 08, 2011 8:27 am
Posts: 159
Location: outer Shpongolia
In pure bash(1):

Code:
#!/bin/bash                                                                                                                   
for f in *; do
    if [[ ! -f $f ]]; then
        continue
    fi 
   
    while read -r; do
        lines+=("$REPLY")
    done < "$f"
   
    set -f; words=(${lines[@]}); set +f

    printf 'Filename: %s\n' "$f"
    printf '%9s|~> words: %d\n' ' ' "${#words[@]}"
    printf '%9s|~> lines: %d\n\n' ' ' "${#lines[@]}"
    unset 'lines'
   
    files+=("$f")
done

printf 'The current directory has %d files.\n' "${#files[@]}"
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