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I am a little confused about making newline to behave as intended. whether i use double quotes or single or escape twice, i.e \\n, the newline gets printed as a literal character. I don't seem to understand what my confusion is right now. help pls.
script follows:
#!/bin/bash
#showing function positional paramters
fxneg () {
echo "get the function name, which is $FUNCNAME."
echo "special parameter 0 is $0."
echo "this is the first argument passed, which is $1."
return
}
fxneg muteman
echo "now that the function is executed,"
echo "special parameter 0 is now $0.\n"
echo "and the number of arguments is $#."
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