Bashscripts.org

Hi,

I've a well unterstood problem, I wonder if there is a solution to it exists.

I've a script, let's call it qwe. qwe calls script asd, which finds an update(zxc) for script qwe and updates it. When it gets back to qwe, it continues to run the updated script zxc from the location where it left after calling asd.

What I want to do is, let shell load qwe. Run it in memory and do not go back to updated zxc after asd quits, and just continue to run qwe till the end.

Thanks in advance,
Ozgur

Files:

qwe

asd

zxc

There was a very similar question in the basics forum ... what's going on?

To keep it simple: do not modify interpreted scripts while running and expect reasonable results! There is always a better way. In this case, just use exec. This will replace the running instance with whatever script you call. You can use this in qwe (and zxc, which replaces qwe). For example:

qwe

I tried this, but it never comes back from asd to qwe again, it runs asd till end and quits. this is not exactly what I want.

Sorry, your specifications from the first post weren't clear to me. Your example qwe terminates after calling asd.

if you want to continue running qwe after calling asd, just call asd normally: "./asd" or similar. However, if qwe is going to continue to run, you should not overwrite qwe while it is running. As a general rule, self-modifying source code is a bad idea, but when it's an interpreted language, you really just cannot do it.

Could you give something closer to the exact code that you are using? I can't accurately recommend what you should do at this point.

- thobbs

Sorry I can't. Actual files are really big. But I update my sample scripts to reflect my expectations. Here they are:

qwe


asd


zxc


expected output from qwe


actual output

Why not just wait until qwe is done to copy zxc onto qwe? You're not running the zxc code during the execution of qwe anyway.

Just call "qwe && cp zxc qwe", or write a script that basically does the same thing.