Bashscripts.org

I have created this test that works correctly if the user input is any number or letter but fails for any other input including a simple carriage return. Is there a better way to do this so it will work correctly for any input?
#!/bin/bash
#source pick Option START*********************************************
function pickOption()
{
OPTION="0"
while true;
do
if (( "$OPTION" < "1" )) || (( "$OPTION" > "3" )); then
echo "Select an option:"
echo "1. Do one "
echo "2. Do two "
echo "3. Do three "
read OPTION
else
break
fi
done
echo "option = " $OPTION
}
#source pick Option END*********************************************
##main##
pickOption
echo "option = " $OPTION

In the style of what you already have;



I wouldn't do it this way myself, I'd probably use the "case" command.

DW

Thank you DW. It works now. I didn't try the case command as I would have had the same verification problem.
Thanks again.
chas.........