Bashscripts.org

Hi all,

I'm in need of a script that gets me the log files of today & yesterday, as in the following example:

(where YYMMDD is today's date)

so for today it would be:


How do I do this...?

This is something I've never really figured out the best way to do... It's pretty easy to get today's date in the format that you want with something like:



The problem is getting yesterday's date. Since the "day" is the last field, you could take today's date and subtract 1, but that won't work on the first of the month. I've seen a lot of stuff in *nix that uses Unix time (great article on wikipedia: http://en.wikipedia.org/wiki/Unix_time) to make it easy to do math on it, but converting back and forth can be a pain.

Thanks to you, I have learned something new today, and it's so simple! To get yesterday's date, try this:



So to match those two files with yesterday's date and today's, you can do something like this:



Hope this helps!

It sure does! Thank you!

Now my server logs are totally automatically processed in awstats

I had already started to look into using php, but bash is so much easier!

You do not need the internal date and also 'yesterday' can be used instead of '1 day ago' the following is good;

Shiny!

You could also just use find to do this. I believe something like this should work fine:


Best regards
Fredrik Eriksson