I am writing a script in which a query is taken at the beginning of the script to be later used at the end. In the query, variables are generated from a loop, and I would like to assign the variable NAME (not value) with an appended 1, 2, 3, 4.....n. The number of loops varies according to the circumstance.
So for example, I get:
$pattern1, $pattern2, $pattern3...etc
The problem I have is that these variables are used later in the script in a loop, in which the first pass of the loop needs to call the first $pattern1, the second pass should call $pattern2, etc.
How do I dynamically call each variable in its sequence?
If I try something like incrementing a variable called "pass" each time, and then appending it to pattern:
I merely get the concatenation of the two (which simply is the value of $pass, since $pattern is not set).
I have tried things like:
but only get errors.
Any ideas on how to call variables in this way?
At the beginning of the script where I am originally assigning values to the $pattern/n variables, I am also naming them dynamically, using
so when pass=1 I end up with a variable called pattern1 with the value of value.
(simply typing pattern$pass=value does not work, I had to explicitly use the let command.)
This works fine, but I run into trouble when I want to place forward slashes around value in order to substitute it in a sed script, eg,
I get an error from let saying operand expected.
Does anyone know how I might accomplish this?
I can work around this one, but I would rather find out how to do what I want to do.Thank you,